- #1
blayman5
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Homework Statement
Two blocks are arranged at the ends of a mass-
less string as shown in the figure. The system
starts from rest. When the 1.81 kg mass has
fallen through 0.336 m, its downward speed is
1.25 m/s.
The acceleration of gravity is 9.8 m/s2 .
at is the frictional force between the
3.13 kg mass and the table? Answer in units
of N.
The Attempt at a Solution
m(table) T-friction=m(table)a
m(fallen) T-m(fallen)g=m(fallen)a
T=m(fallen)a-m(fallen)g
T=9.3215
T-friction=m(table)a
-(coeff)N=m(table)a-T
(coeff)N=T-m(table)a
coeff=t-m(table)a
-----------
m(table)g
=.1706
Did I go about this correctly?