1. The problem statement, all variables and given/known data Two blocks are arranged at the ends of a mass- less string as shown in the figure. The system starts from rest. When the 1.81 kg mass has fallen through 0.336 m, its downward speed is 1.25 m/s. The acceleration of gravity is 9.8 m/s2 . at is the frictional force between the 3.13 kg mass and the table? Answer in units of N. 3. The attempt at a solution m(table) T-friction=m(table)a m(fallen) T-m(fallen)g=m(fallen)a T=m(fallen)a-m(fallen)g T=9.3215 T-friction=m(table)a -(coeff)N=m(table)a-T (coeff)N=T-m(table)a coeff=t-m(table)a ----------- m(table)g =.1706 Did I go about this correctly?