# Friction Equilibrium Problem

1. Nov 21, 2008

### Oblivion77

1. The problem statement, all variables and given/known data

2. Relevant equations

Sum of forces in x,y and f/N=coefficient of friction

3. The attempt at a solution

I am not sure where to begin, I think each member there is a 2 force member. I already found the minimum coefficient of friction by doing Tan(8)

2. Nov 21, 2008

### Topher925

3. Nov 21, 2008

### Oblivion77

Thanks, would I need to use both members or can I only use the bottom member to find the answer?

4. Nov 22, 2008

### Oblivion77

Are you sure that is correct? I didn't know the y component of the normal is the friction? If there was just the normal what would be the other unknown?

5. Nov 23, 2008

### Oblivion77

anyone have any ideas? I tried some stuff, and got an answer as 9.15N. Not sure if that is correct.

Last edited: Nov 23, 2008
6. Nov 25, 2008

### Oblivion77

Still stuck on it.

7. Nov 25, 2008

### LogicalTime

try and break it down into forces in y direction and forces in x direction

here is what I get for the y direction, T is the tension force
$T_{1} \cos (30^{ \circ }) + T_2 \sin( 8^{\circ}) -mg = 0$

try and get the x direction forces into an equation