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Friction Equilibrium Problem

  1. Nov 21, 2008 #1
    1. The problem statement, all variables and given/known data


    2. Relevant equations

    Sum of forces in x,y and f/N=coefficient of friction

    3. The attempt at a solution

    I am not sure where to begin, I think each member there is a 2 force member. I already found the minimum coefficient of friction by doing Tan(8)
  2. jcsd
  3. Nov 21, 2008 #2
  4. Nov 21, 2008 #3
    Thanks, would I need to use both members or can I only use the bottom member to find the answer?
  5. Nov 22, 2008 #4
    Are you sure that is correct? I didn't know the y component of the normal is the friction? If there was just the normal what would be the other unknown?
  6. Nov 23, 2008 #5
    anyone have any ideas? I tried some stuff, and got an answer as 9.15N. Not sure if that is correct.
    Last edited: Nov 23, 2008
  7. Nov 25, 2008 #6
    Still stuck on it.
  8. Nov 25, 2008 #7
    try and break it down into forces in y direction and forces in x direction

    here is what I get for the y direction, T is the tension force
    T_{1} \cos (30^{ \circ }) + T_2 \sin( 8^{\circ}) -mg = 0

    try and get the x direction forces into an equation
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