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Friction Force

  1. Oct 21, 2008 #1
    1. The problem statement, all variables and given/known data
    A force of 105N is applied horizontally to a 20.0 kg box to move it across a horizontal floor. If the box has an acceleration of 3.00 m/s^2, find the coefficient friction.

    2. Relevant equations
    coefficient friction = Ff/Fn

    3. The attempt at a solution
    I converted the mass into newtons so 20.0 kg = 196 N
    I have no idea how to do this. I drew a picture, but I don't know what to do with the acceleration.
  2. jcsd
  3. Oct 21, 2008 #2


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    Ok. What would the acceleration be if there was no friction?

    Won't the difference then be how much friction has retarded its motion?
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