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Friction help?

  1. Oct 30, 2008 #1
    1. The problem statement, all variables and given/known data

    If you use a horizontal force of 30.0N to slide a 12.0-kg wooden crate across a floor at a constant velocity, what is the coefficient of kinetic friction between the crate and the floor?

    2. Relevant equations


    3. The attempt at a solution

    I thought maybe it would be 30.0N=[tex]\mu[/tex]k(12.0kg)(9.8m/s290, but I dunno if that's right. Is 30N the force of friction? Please help me!
  2. jcsd
  3. Oct 30, 2008 #2

    Doc Al

    User Avatar

    Staff: Mentor

    You are doing fine. Yes, the 30N force = force of friction. (Since the box moves with constant velocity, what must be the net force on it? That's what should convince you that the applied force and the friction must be equal and opposite.)
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