- #1
Hypnos_16
- 153
- 1
Homework Statement
A 5.13-kg block is placed on top of a 11.0-kg block that rests on a frictionless table. The coefficient of static friction between the two blocks is 0.675. What is the maximum horizontal force that can be applied before the 5.13-kg block begins to slip relative to the 11.0-kg block, if the force is applied to the more massive block?
m1 = 5.13kg
m2 = 11.0kg
µ = 0.675
Homework Equations
i tried getting the Frictional force of the block sitting on the other block and came up with 34 Newtons. i figured since the Frictional Force of one block on the other is 34 then then that would be the greatest force that could be applied, after attempting this i came up with the wrong answer... I'm stumped
The Attempt at a Solution
Ff = µFn
Ff = (0.675)(5.13 x 9.8)
Ff = 34.0N