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Friction on a rotating disk

  1. Feb 3, 2013 #1
    1. The problem statement, all variables and given/known data

    The thing that is lying on the disk(Disko), is rotating together with disko. After the rotary frequency of disko grew twice (N X 2), friction(rubbing) Force grew F=6 ( F + 6). You have to understand friction Force module at the original frequency.


    2. Relevant equations

    I don't know. Probably, 2N = F + 6 : m X g

    3. The attempt at a solution

    2N = F6 : mg = F6 : 9,8
    F = 9,8 : 6

    but I don't think it is correct please help me. Sorry if there are some mistakes but I really need it please do not delete this post.
    Thank you very much. :)
     
  2. jcsd
  3. Feb 3, 2013 #2

    tiny-tim

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    Welcome to PF!

    Hi 5Mystery! Welcome to PF! :smile:

    The only horizontal force is the friction (and the only motion is horizontal).

    So you can find the friction, F, by using F = ma.

    So what is the acceleration (a), at an angular frequency ω? :wink:
     
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