Solving Maximum Acceleration for 4WD Car on Dry Road

[jhk_1945]

A car with four-wheel drive has a mass of 1000kg. Its weight is evenly distributed on its four wheels. The coefficient of static friction with the dry road is 0.8. The car starts from rest on a horizontal surface. What is the greatest forward acceleration that the car can ahcieve without spinning its wheels?

I simply said F = mu x Fn
= 0.8x1000x9.8=7840N

and divided that by the mass to get 7840 / 1000 = 7.84 m/s^2

But I feel that this is isn't correctly answering the question. Can anyone please help me out!?

Thanks

 

[blackwizard]

I don't see what else u could do. Seems perfect 2 me

 

[kyle8921]

for your question. Your approach to solving for the maximum acceleration of the 4WD car is correct. The formula F = μFn is used to calculate the maximum static friction force, where μ is the coefficient of static friction and Fn is the normal force acting on the car. In this case, the normal force is equal to the weight of the car, which is evenly distributed on all four wheels.

To find the greatest forward acceleration that the car can achieve without spinning its wheels, we need to use Newton's second law of motion, which states that the net force acting on an object is equal to the mass of the object multiplied by its acceleration (F = ma). In this case, the net force is the maximum static friction force, and the acceleration we are trying to find is the greatest forward acceleration.

So, using F = ma, we can rearrange the formula to solve for acceleration: a = F/m. Plugging in the values we have, we get a = 7840 N / 1000 kg = 7.84 m/s^2. This means that the greatest forward acceleration the car can achieve without spinning its wheels is 7.84 m/s^2.

I hope this helps clarify your solution to the problem. Keep up the good work in your scientific studies!