(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A ball horizontally with an initial velocity of 5m/s,and the ball stops at 8.0m. Find the force of friction if the coefficient is 0.3.

2. Relevant equations

##F_net=ma##

##v^2=v_0^2 2ax##

## a=\frac{v_1^2 - v_0^2}{2ax}##

##f=μN##

##N=mg## (In this case the normal force is equal to weight.)

3. The attempt at a solution

## a=\frac{v_1^2 - v_0^2}{2ax}=\frac{-25\frac{m^2}{s^2}}{16m}=-1.56\frac{m}{s^2}##

##F_net=ma##

##f=ma##

##μN=ma##

##μmg=ma##

##μg=a##(Masses cancel out because the mass doesn't matter on rotary bodies.

##μg=a## I'm stuck here, how can I find the friction?!

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# Friction problem

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