JOOOOOOOOOOOOOOOOOONWOOOOOOOOOOOOOOOOO NHOOOOOOOOOOOOOOOOOOOOOOOOOOO do your physics hw nooooooob
the 'x' one is correct.
For the 'y' one, the resultant force perpendicular to the plane is 0 so -490cos30+N = ? (so what is N?)
Hi zhangsterii, welcome to PF.
Since crate is moving down a should be...... ?
In the y direction there is no motion. So in that direction acceleration is zero.
Now what is the frictional force f?
chico was here
For both x and y you have written 50a. How is it that?
JONNYWOorking on part 2
how should the x= and y= equations be set up??
When the particle will have uniform velocity in the upward direction?
umm wat are u talking about?
I am asking "when the particle moves with uniform velocity?" Refer Newtons first law.
when there is no accerlation
When the acceleration is zero on an inclined plane with friction?
that doesnt make sense...your wording
when velocity is constant
Now If you pull the crate in the upward direction, what is the direction of the frictional force?
What is the net down ward force?
To move the crate with uniform velocity, how much force you have to apply?
Separate names with a comma.