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**Advanced Road Bank question**

## Homework Statement

There is a road bank designed for 60km/hr (16.7 m/s) with a radius of 70m and no friction. What is the top speed with a mew of 0.8[tex]\mu[/tex] ?

G=gravitational constant

V=16.7m/s

## Homework Equations

Tan[tex]\theta[/tex]=V^2/(R*G)

Fc=(M*V^2)/R

## The Attempt at a Solution

First I calculated the angle at which the car wont move with no friction and I got 22.124

Then I started filling in what I knew:

Fnormal:=(G*sin([tex]\theta[/tex]))+(Fc*Sin(90-[tex]\theta[/tex])) The component of gravity added to a component of Centripetal force.

then:

Ffriction:=Mew*Fnormal

Fc:=Ffriction+the component of fnormal pushing back against the Fc.

(M*V^2)/R=Mew*((G*sin([tex]\theta[/tex]))+(Fc*Sin(90-[tex]\theta[/tex])))the component of fnormal pushing back against the Fc.

But I don't know if I'm on the right track or completely wrong.

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