1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Frictional force

  1. Nov 18, 2004 #1
    A horizontal force of 12 N pushes a 0.5 Kg block against a vertical wall. The block is initially at rest, If static and kinetic coefficients are 0.6 and 0.8 respectively what is the friction force?

    Basically the fbd has Force of 12 N across the x component(+) and the Normal force in the opposite (-ve)... The y component is positive facing downwards thus Fnety=mg-frictionforce=ma(y)... Friction force is equal to coefficient of static x Normal... static is 0.6 and Normal force is 12 N, which gives 7.2 N, right?

    (i am doubting myself because some other ppl didnt get that)

  2. jcsd
  3. Nov 18, 2004 #2
    Thats an odd question.

    The static Ff would seem to be lower then the kinetic Ff
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Similar Discussions: Frictional force
  1. Frictional Forces (Replies: 1)

  2. Friction and forces? (Replies: 6)

  3. Force and Friction (Replies: 4)