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Frictional Forces

  1. Nov 12, 2012 #1
    1. The problem statement, all variables and given/known data

    A baseball player slides into third base with an initial speed of 7.9 m/s. If the coefficient of kinetic friction the player and the ground id .41, how far does the player slide before coming to rest

    2. Relevant equations

    vf^2=vi^2 + 2ad
    kf=μm

    3. The attempt at a solution
    I tried subsituting but I need acceleration and distance. I didn't know where to go from there
     
  2. jcsd
  3. Nov 12, 2012 #2
    Are you given mass of the baseball player?
     
  4. Nov 12, 2012 #3
    sorry, yeh you're right with the formula

    but why is the normal force equal to gravity and what is FUN
     
  5. Nov 12, 2012 #4
    Sorry, do you have mass?
     
  6. Nov 12, 2012 #5
    No, no mass is given
     
  7. Nov 12, 2012 #6

    Doc Al

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    Use Newton's 2nd law to find the acceleration. The only force acting (at least horizontally) is friction.

    Just call the mass 'm'. You won't need an actual value.
     
  8. Nov 12, 2012 #7
    I don't understand. F=ma so a=F/m but we don't have an F. I don't really understand frictional forces at all
     
  9. Nov 12, 2012 #8

    tiny-tim

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    Welcome to PF!

    Hi Confused too! Welcome to PF! :smile:
    You have the coefficient of frictionk = 0.41) …

    so if the mass is m, what is the friction force? :wink:

    (btw, you can then use the work energy theorem)
     
  10. Nov 12, 2012 #9
    Re: Welcome to PF!

    thanks :smile:

    But we're not given m and what's the work energy theorem?
     
  11. Nov 12, 2012 #10

    haruspex

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    Re: Welcome to PF!

    So create an unknown for it (m?) and with luck it will cancel out of the equations later.
    In this case, that the kinetic energy lost by the player is equal to the work done sliding against friction. But you might as well stick with the equations you quoted. (The second one is more accurately written kf=μmg.)
     
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