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Frictional Forces

  1. May 31, 2014 #1
    1. The problem statement, all variables and given/known data

    In the attachment


    2. Relevant equations

    F = ma
    F = mg
    Ffriction < μ*N

    3. Attempt at a Solution

    Okay so I know that the weight is weighing down with a gravitational force of ~750 N. Similarly, I know that the two forces on the wall will both provide frictional forces pointing up with a magnitude equal to μ*F.

    So I set (mg)/2 = μ*F and got something along the lines of 910 Newtons. I'm convinced this is correct because I can see no other way to do it. The book's answer is 52 Newtons which doesn't make sense because you'd have a combined force of 104 Newtons holding up a gravitational force of ~750 Newtons.

    I'm looking for someone to either confirm that I'm doing it correct or point out what I'm doing wrong. Thanks.
     

    Attached Files:

  2. jcsd
  3. May 31, 2014 #2
    I get the same answer as you.

    Chet
     
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