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Frictionless Bank

  1. Sep 27, 2006 #1
    Which force is responsible for holding a car in a frictionless banked curve?

    The answer is the horizontal component of the normal force. But could anyone explain why that is?

    I thought it would be the horizontal component of the weight since normal force is vertical?
     
  2. jcsd
  3. Sep 27, 2006 #2

    Doc Al

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    Staff: Mentor

    The weight acts vertically--it has no horizontal component. The normal force is perpendicular to the road surface; since the road is banked (at an angle) that normal force is not vertical.
     
  4. Sep 28, 2006 #3
    This is a rotational velocity problem. There are two kinda 'normal' forces here. The real vertical normal force to resist gravity, and the horizontal force in the 'normal' directionto accelerate the object along a curve.
     
    Last edited: Sep 28, 2006
  5. Sep 28, 2006 #4

    Doc Al

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    This is a problem involving circular motion and thus centripetal acceleration. There is only one normal force, which is perpendicular to the road surface. That normal force has vertical and horizontal components.
     
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