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Frobenius method

  1. Nov 25, 2005 #1
    for the frobenius method, why do you suppose that a0=1?
  2. jcsd
  3. Nov 26, 2005 #2


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    You don't. You assume that it is non-zero which is just a choice of "c".

    The idea of Frobenius method is to write a solution in the form
    [tex]\Sigma_{n=0}{\infnty}a_n x^{n+c}[/tex]
    where c, while a constant, is not necessarily a positive integer.
    If I, choosing c to be, say, c0[/sup], I find that a0= 0 but a1 is not, I could just take c= c0+ 1 instead.
  4. Nov 27, 2005 #3
    thank you very much!!! :)
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