# Frobenius method

1. Nov 25, 2005

### asdf1

for the frobenius method, why do you suppose that a0=1?

2. Nov 26, 2005

### HallsofIvy

Staff Emeritus
You don't. You assume that it is non-zero which is just a choice of "c".

The idea of Frobenius method is to write a solution in the form
$$\Sigma_{n=0}{\infnty}a_n x^{n+c}$$
where c, while a constant, is not necessarily a positive integer.
If I, choosing c to be, say, c0[/sup], I find that a0= 0 but a1 is not, I could just take c= c0+ 1 instead.

3. Nov 27, 2005

### asdf1

thank you very much!!! :)