- #1

mhill

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[tex] \int_{0}^{\infty} dt \frac{ f(at)-f(bt)}{g(t)}= (G(b)-G(a))(f(0)-f(\infty)) [/tex]

and [tex] \int dt g(t) [/tex]

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- Thread starter mhill
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- #1

mhill

- 188

- 1

[tex] \int_{0}^{\infty} dt \frac{ f(at)-f(bt)}{g(t)}= (G(b)-G(a))(f(0)-f(\infty)) [/tex]

and [tex] \int dt g(t) [/tex]

- #2

HallsofIvy

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Did you mean to say

[tex]G(t)= \int dt g(t) [/tex]

in your last line?

[tex]G(t)= \int dt g(t) [/tex]

in your last line?

- #3

mhill

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- #4

HallsofIvy

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[tex]\frac{f(b)- f(a)}{g(b)- g(a)}= \frac{f'(c)}{g'(c)}[/tex]

That looks like an integral version to me.

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