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Frustum Pyramid

  1. May 27, 2010 #1
    I had a similar question in the "engineering systems and design" category but didn't get any replies so hear is the simple version involving only the math.

    Basically I just need to see if I am using the correct formula to the calculate the volume of a frustum pyramid. However the bottom of the pyramid is a 24"x24" square and the top would be a place which much much larger 6 sided shape, with all sides different lengths. I just need to know if this formula will work for a frustum pyramid with a square for one plane and a 6 sided shape for the other plane and a depth of 4" Here is my math.

    This is not a school related question.

    The formula was found on wikipedias entry for a frustum pyramid

    Height = 4 inches Area 1 = 713392”
    Area 2 = 756” (24”x24”)

    Volume = (height *area1) – (height*area2)

    = ( 4” * 713392”) -( 4” * 576”)

    Volume = 2851264 inches cubed

    Convert to feet cubed ( 1 ft^3 = 144 in^3

    2851264 / 144 = 19800.44 feet cubed
  2. jcsd
  3. May 27, 2010 #2
    Last edited by a moderator: May 4, 2017
  4. May 27, 2010 #3
    Ok i see, I wanna use that one because in my case the apex has allready been sliced off so I'm not finding the difference between a full pyramid and one with a flat top.

    There was a mistake up there in my math the volume should actually be 950181.33 and the i pasted the formula in from word so it didn't show my underline which was intended to show division but anyways.

    Also what is the difference between this and the heronian mean.


    Running the formula this way gives me an even smaller number almost 4 times smaller.
  5. May 27, 2010 #4
    [itex]a_1=24^2, a_2=713392, h=4 [/itex]


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