# Function and Geometry

1. Feb 28, 2008

### shawqidu19

1. The problem statement, all variables and given/known data

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The function defined on R by f(x)= 2/3x+2

And cf his graphic representation in an orthonormal mark (o; i; j)

On the X axis, we consider points A, B and H of respective abscissas 3, -3 and x (x belongs R)

Or C the point of Cf of the same abscissa as A and M the point of Cf of abscissa x

1°) Make the complete figure ?

2°) Calculate the distances AH and MH according to x and by means of the absolute values ?

3°) To determine for which value (s) of x the areas of triangles CHA and MOB is equal ?

Please Anyone for help me, Can u drwan this graphic please please and represents all points A B H M and C

2. Relevant equations

3. The attempt at a solution

2. Feb 28, 2008

### HallsofIvy

Did you repost this? I remember responding to post where both A and B had abscissa 3! It would have been better to add your correction to the same thread.

Okay so C also has abscissa (x-value) 3 and is on the graph y= (2/3)x+ 2 so y= (2/3)(3)+ 2= 4. C is the point (3, 4). Similarly, M is the point (x, (2/3)x+ 2).

Surely, if you are doing a problem like this, you know that the graph of a function like this is a straight line? When x= -3 (as with point B), y= (2/3)(-3)+ 2= -2+ 2= 0. The graph is the straight line that passes through (-3, 0) and (3, 4).

3. Feb 28, 2008

### shawqidu19

Function Geometry

4. Feb 29, 2008

### shawqidu19

Function ax+b

5. Feb 29, 2008

### HallsofIvy

No, I am not going to draw a straight line for you! I have already told you that the graph is the straight line passing (-3, 0) and (3, 4). If you can't draw that you need more help than I can give you.

6. Feb 29, 2008