1. The problem statement, all variables and given/known data A man runs at a speed of 4.0 m/s to catch a standing bus. When his distance to the door is 6.0 m, the bus starts moving forward and continues with a constant acceleration of 1.2 m/s2. 1. How many seconds does it take for the man to reach the door ? 2. If at the beginning he is 10.0 m from the door, will he (running at the same speed) ever catch up? 2. Relevant equations S=vt S=1/2 at2 3. The attempt at a solution 1. Solution for the first question. Function for the man displacement is: Sman=4t+6 Function for the bus displacement is: Sbus=1/2(1.2)t2=0.6t2 When the man catches the bus: Sman=Sbus ↔ 4t+6 = 0.6t2 ↔ 0.6t2-4t-6 = 0 (t>0) → t≈ 7.9 s. 2.Solution for the second question. If at the beginning he is 10.0 m from the door, function for his displacement is: Sman=4t+10 Sman=Sbus ↔ 0.6t2-4t-10 = 0 (t>0) → t ≈ 8.6 s Therefore if at the beginning he is 10 m from the door, he will catch the bus after 8.6 s. I wonder if my solutions are correct? because I'm not sure whether I should add 6 meters and 10 meters or subtract them from the displacement function of the man ?