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Fundamental Frequency

  1. Mar 10, 2008 #1
    My question goes as follows:

    An open pipe in air is designed to produced 2 successive harmonics at 235 Hz and 275 Hz at 20 degrees Celsius.
    What is the fundamental frequency?
    What is the length of the pipe (m)?

    I'm not sure how to solve this problem, as I can't find the equation to properly relate the information I have. Would you use Frequency=V/2L?

    I'd like to apologize for posting this in the physics thread, it was an accident.
     
  2. jcsd
  3. Mar 10, 2008 #2

    pam

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    1. Calculate each wavelength.
    2. [tex]\lambda_n-\lamdba_{n+1}=\lambda_0/2[/tex].
    3. [tex]f=c/n\lambda_0[/tex]
    4. [tex]L=2\lambda_0[/tex].
     
    Last edited: Mar 10, 2008
  4. Mar 10, 2008 #3
    So the wavelength equals velocity over frequency. Velocity equals 331+0.6*T (C) correct? So find the velocity and divide it by both frequencies and subtract the second from the first, then multiply by two, and that should give me the fundamental wavelength (lambda not)?
     
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