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## Main Question or Discussion Point

Why must the 4-momentum for photons [tex] p^\mu =(\frac{h\nu}{c},\frac{h\nu}{c} \textbf{e}) [/tex] transform as a 4-vector in Special Relativity?

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Why must the 4-momentum for photons [tex] p^\mu =(\frac{h\nu}{c},\frac{h\nu}{c} \textbf{e}) [/tex] transform as a 4-vector in Special Relativity?

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Dale

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CompuChip

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You can even derive it (Let [itex]p^\mu = (p^0, \vec{p})[/itex], apply a Lorentz transformation and you will see what p

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