A slide loving pig slides down a certain 19° slide in twice the time it would take to slide down a frictionless 19° slide. What is the coefficient of kinetic friction between the pig and the slide? here is how i approached the problem: since on a slide i changed the x-axis going with the slide with positive heading down and the y-axis facing in the n((Force normal) direction of the pig). i split up the weight force into: Wy = -(W)cos(19) Wx = (W)sin(19) and I also know that Fk = n Mk (Mk = coefficient of kinetic friction (mew k)) since there is no acceleration in the y-direction it is safe to say Wy = n so. . . in the x-direction Fnetx = ma (acceleration in x-direction) break that down to. . . Wx - Fk = m a (acceleration in x direction) The part I am confused about is what does the time have to do with this problem and since i am not given the mass of the pig I can not go any further. . . any tips to keep me going?