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Fusion of ice

  1. Jul 9, 2010 #1
    1. The problem statement, all variables and given/known data

    A piece of ice at-10 centigrade is heated to -1 C using a certain quantity of energy. Then another 20 times as much energy is necessary to finally obtain water. Using that the specific heat of ice is half of the specific heat of 4.2 kJ/(kg oC) of water, determine the heat of fusion of ice from the above measurement data.


    2. Relevant equations
    Q=mct
    Q=mL


    3. The attempt at a solution
    Assuming heat to be Q
    and mass m

    Q=mct
    Q=m x 2.1 x 9

    and also

    20Q = m x 2.1 x 1
    Equating
    m x 2.1 x 9 x 20 = m x 2.1 x 1

    (This is wrong since Fusion of ice didnt come into picture... so any help appreciated)
    (Also this is not a homework question... just one which I saw in some book )
     
  2. jcsd
  3. Jul 9, 2010 #2
    The problem says 20 much more energy is required to get WATER. So your second equation:

    20Q = m*2.1*1 is wrong, it's supposed to be:

    20Q = m*2.1*1 + mL

    -Tusike
     
  4. Jul 9, 2010 #3
    Thanks a lot Tusike .
     
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