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FWHM of a gaussian function

  1. Apr 20, 2010 #1

    I have a gaussian of the form

    I know that the FWHM=0.939A, but I cannot prove it.

    I Let [tex]exp[-\frac{\pi*x^{2}}{A^2}=0.5[/tex] (i.e. the half maximum part)

    taking natural logs I get rid of the exponential, but then which bit represents the full width?
  2. jcsd
  3. Apr 20, 2010 #2


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    Write x = kA and compute k=(-ln(.5)/π)1/2

    Your Gaussian looks funny.
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