Since the pi^0 decays to two photons its C-parity is +1, but its isospin ket is $$|1,0\rangle,$$ which makes it a little tricky to understand why its G-parity is -1. Does the rotation around the I_2 axis somehow generate a minus sign? This seems odd since the isospin ket points into the x-y plane, so it seems the rotation by pi wouldn't affect it.(adsbygoogle = window.adsbygoogle || []).push({});

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# G- and C-parity of the pi^0

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