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G-loading on aircraft (simple)

  • Thread starter marklar13
  • Start date
  • #1
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Homework Statement

Consider an aircraft flying with speed 300 ft/s in a steady pull-up maneuver with pitch rate q = 0.1 rad/sec.

What is the g-loading experienced by the pilot of the aircraft just as the maneuver begins (i.e. when the aircraft is still level)?

The attempt at a solution

So the first step is to find the radius of curvature of the maneuver from:

R=V/q=(300 ft/s)/(0.1 rad/s) --> R=3000 ft

Then, I believe you find the acceleration of the aircraft from:

G=(V^2)/R=(300^2)/3000 --> G=30 ft/s^2

So, since 1 g = 32.174 ft/s^2

The g force (without earth's g) is 30/32.174=.932 g

Adding that to the 1 g due to earth the answer would be 1.932 g?

Is that correct?
 
Last edited:

Answers and Replies

  • #2
tiny-tim
Science Advisor
Homework Helper
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hi marklar13! :smile:

Then, I believe you find the acceleration of the aircraft from:

G=(V^2)/R=(300^2)/3000 --> G=30 ft/s^2

So, since 1 g = 32.174 ft/s^2

The g force (without earth's g) is 30/32.174=.932 g
yes that's fine :smile:

(though you could save time by using ωv for the centripetal acceleration … ωv = ω2r = v2/r :wink:)
 

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