# G-parity question

1. May 25, 2005

### kakarukeys

why G parity = $$(-1)^I C$$?
C is the Charge conjugation number of the neutral member.

G parity of $$\pi^0$$ is very obvious. Given $$e^{i\pi I_2} |I\ 0\rangle = (-1)^I |I\ 0\rangle$$

How do you compute the G parity of $$\pi^+$$?

G parity operator
$$G = Ce^{i\pi I_2}$$

2. May 25, 2005