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G-parity question

  1. May 25, 2005 #1
    why G parity = [tex](-1)^I C[/tex]?
    C is the Charge conjugation number of the neutral member.

    G parity of [tex]\pi^0[/tex] is very obvious. Given [tex]e^{i\pi I_2} |I\ 0\rangle = (-1)^I |I\ 0\rangle[/tex]

    How do you compute the G parity of [tex]\pi^+[/tex]?

    G parity operator
    [tex]G = Ce^{i\pi I_2}[/tex]
     
  2. jcsd
  3. May 25, 2005 #2
    Last edited: May 25, 2005
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