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G-parity question

  1. May 25, 2005 #1
    why G parity = [tex](-1)^I C[/tex]?
    C is the Charge conjugation number of the neutral member.

    G parity of [tex]\pi^0[/tex] is very obvious. Given [tex]e^{i\pi I_2} |I\ 0\rangle = (-1)^I |I\ 0\rangle[/tex]

    How do you compute the G parity of [tex]\pi^+[/tex]?

    G parity operator
    [tex]G = Ce^{i\pi I_2}[/tex]
  2. jcsd
  3. May 25, 2005 #2
    Look at http://ej.iop.org/links/q19/gde,d+XMMgTmN65bCrJ,UA/ejv11i2p99.pdf [Broken]
    http://www.phys.ualberta.ca/~gingrich/phys512/latex2html/node64.html [Broken]

    Charge conjugation is determined by how physical entities (like the E field) change if you replace a charge by its opposite(this is what the charge conjugation operator does)...For example E will be come -E if you replace q by -q


    to see how it is done : www.physics.ohio-state.edu/~kass/P780_L6_sp03.ppt
    Last edited by a moderator: May 2, 2017
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