# G-parity question

1. May 25, 2005

### kakarukeys

why G parity = $$(-1)^I C$$?
C is the Charge conjugation number of the neutral member.

G parity of $$\pi^0$$ is very obvious. Given $$e^{i\pi I_2} |I\ 0\rangle = (-1)^I |I\ 0\rangle$$

How do you compute the G parity of $$\pi^+$$?

G parity operator
$$G = Ce^{i\pi I_2}$$

2. May 25, 2005

### marlon

or
http://www.phys.ualberta.ca/~gingrich/phys512/latex2html/node64.html [Broken]

Charge conjugation is determined by how physical entities (like the E field) change if you replace a charge by its opposite(this is what the charge conjugation operator does)...For example E will be come -E if you replace q by -q

marlon

to see how it is done : www.physics.ohio-state.edu/~kass/P780_L6_sp03.ppt

Last edited by a moderator: May 2, 2017