1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Galaxy Mass with Dark Matter

  1. Nov 2, 2013 #1
    1. The problem statement, all variables and given/known data
    Suppose that a sprial galaxy has the mass profile:

    ##M_{disk}(r)=M_d[1-(1+\frac{r}{r_{rd}})e^{-\frac{r}{r_{rd}}}]##

    Where rrd=3Kpc. and Md is unknown.

    Like all galaxies, this galaxy also contains dark matter as well as its luminous matter. Using the rotational velocity data, you will separately measure the masses of both components, spiral disk and dark matter halo.

    1) Find Mdsuch that the circular velocity predicted by the disk alone would not exceed the observed circular velocity at all radii, even neglecting the contribution from the dark matter?
    2) Assume that the total disk mass Md is equal to the maximal value you computed
    in part (1). The remaining mass must correspond to the dark matter. At the
    Sun's radius of 8 kpc, what is the enclosed mass of dark matter, MDM(8 kpc), and
    how does it compare to the enclosed spiral disk mass at that radius, Mdisk(8 kpc)?

    2. Relevant equations

    ##v_{circ}=\sqrt{\frac{GM(r)}{r}}##

    3. The attempt at a solution

    From the data I've been given I find the highest velocity and it's corresponding radius. I plugged this into given equation and plug that into the circular velocity equation. I also converted all of the Kpc to meters and the Km/s to m/s.

    so:
    [tex]v_{circ}=\sqrt{\frac{GM_d[1-(1+\frac{r}{r_{rd}})e^{-\frac{r}{r_{rd}}}]}{r}}[/tex]
    [tex]v_{circ}^2=\frac{GM_d[1-(1+\frac{r}{r_{rd}})e^{-\frac{r}{r_{rd}}}]}{r}[/tex]
    [tex]v_{circ}^2\frac{r}{G[1-(1+\frac{r}{r_{rd}})e^{-\frac{r}{r_{rd}}}]}=M_d[/tex]
    v=194150m/s
    rrd=3Kpc=9.257(10)14
    r=9Kpc=2.7774(10)15
    1pc=3.086(10)11m

    Substituting these values in I get ≈2(10)36kg

    The second part, I assume, I just do the same calculations but instead of having Md in there I'd have (Md+MDM). But I think, before I even start that this will be nonsense considering the values I have to put in:

    8Kpc=2.4688(10)15m
    v@8Kpc=193979m/s

    [tex]v_{circ}^2\frac{r}{G[1-(1+\frac{r}{r_{rd}})e^{-\frac{r}{r_{rd}}}]}-M_d=M_{DM}[/tex]

    MDM=-9.1(10)34

    Notice that this is negative. I've attached the data I was given. The left column, I assume, is R and the right is v. It wasn't labeled but I think it is safe to assume such things.

    So, what have I done wrong? My galaxy mass seems pretty low considering our own galaxy mass. But I'm not sure where I went wrong. Thanks for any guidance!
     

    Attached Files:

  2. jcsd
  3. Nov 2, 2013 #2

    mfb

    User Avatar
    2016 Award

    Staff: Mentor

    That's not the right datapoint. The disk mass is not allowed to lead to a velocity above the observed one, so you need the datapoint which corresponds to the smallest M_d.
     
  4. Nov 2, 2013 #3
    So, the smallest V of 89 then. I'll work out the calculations again after I make breakfast for my son!
     
  5. Nov 2, 2013 #4
    Okay, everything makes more sense now using that value. Thanks for the help!
     
  6. Nov 2, 2013 #5
    also, i was using the wrong conversion for pc->m. its 10^16 not 10^11
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?
Draft saved Draft deleted



Similar Discussions: Galaxy Mass with Dark Matter
  1. Dark matter (Replies: 3)

Loading...