Hey guy's just found this forum, seems pretty interesting, but I've been nested in my bedroom trying to figure out one little thing that miffed me off, I did it in A level physics a while back and remember understanding it completely.(adsbygoogle = window.adsbygoogle || []).push({});

Just to make the question a little easier I'd like to refer you to the following URL as a referance:

http://www.batesville.k12.in.us/Physics/APPhyNet/lab/experiments/kinematics/inclined_plane.htm

If you look at the vector component map you have the standard right angled triangle that was practically created by Galileo, there is an extra triangle (done in red in the diragram) that is made from a perpendicular line protudeing from the incline and intersecting the vertical line (g).

Why do they make this "Theoretical" triangle in almost all of the diagrams? Couldnt i theoretically just use the practical triangle? have G as the vertical (Rather than H) A still being the inclines vector and have a horizontal intersection line rather then a perpendicular line to A.

I tried doing the math for that rather than the theoretical triangle, comes out (if my math is right) as something like:

Sin*Theta*= G / A

And therefore

Sin*Theta*A = G

Which is wrong evidently because all books use A = GSin*Theta*

Whats wrong with my method (horizontal intersection) over the accepted method (Perpendicular theoretical intersection line) that makes it so bent for math? I know it seems like an annoying little question but it's been nagging me all night

Thanks

Adam K

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# Galileo's Slope (Math question)

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