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Galvanometer homework help

  1. Jul 28, 2014 #1
    A galvanometer of coil resistance 50 Ω deflects full scale for a current of 3.50mA. What series resistance should be used with this galvanometer to construct a voltmeter which deflects full scale for 35.0 V ?

    r=50 Ω I=3.50mA=0.0035 V=35.0v R=?


    I= V/R



    3. The attempt at a solution
    I honestly don't know- There is very little explanation in the unit -Help me get started please?
     
  2. jcsd
  3. Jul 28, 2014 #2

    berkeman

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    Staff: Mentor

    I would recommend that you read the wikipedia article on Galvanometers. That should help you form the mental picture that you need to solve this. If you still have problems with this, post the link to the wikipedia article that you read, and ask specific questions about that material.
     
  4. Jul 29, 2014 #3

    CWatters

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    Science Advisor
    Homework Helper

    First thing to do is draw and label both circuits.

    It's the same galvanometer in both cases. Same deflection required (eg "full scale") so have a think about what else will need to be the same both circuits?
     
  5. Jul 31, 2014 #4
    Ok, So this is what I came up with, does it makes sense?
    R1= 50 Ω Ig= 3.5mA=0.0035A V=35.5V R=? In series , therefore Ig=Iv=I

    V=I/R V=V1+V2=IR1+IR2

    V1= 0.0035/50=0.00007 V
    {V-V1}/ I=R2= 10143 Ω= 10 k Ω
    The voltmeter will consist of a resistance R ser = 10k Ω in series with the galvanometer.
     
  6. Aug 2, 2014 #5

    rude man

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    Gold Member

    No.
    Where did 35.5V come from?
     
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