Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Gamma function calculation

  1. Oct 14, 2011 #1


    take [tex]t=x^2[/tex]




    Why here we can here reducing integrand by [tex]x[/tex]?
  2. jcsd
  3. Oct 14, 2011 #2


    User Avatar
    Science Advisor

    What is your question? You've done the substitution correctly, so you see how the x's cancel. What is the problem?
  4. Oct 14, 2011 #3
    Lower limit is [tex]0[/tex]. Why I may cancel x's?
  5. Oct 14, 2011 #4


    User Avatar
    Science Advisor
    Homework Helper

    Because the functions are defined on intervals not containing the point 0, that's why you can have the x in the denominator and simplify it through.
Share this great discussion with others via Reddit, Google+, Twitter, or Facebook