1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Gamma photon momentum

  1. May 17, 2008 #1
    1. The problem statement, all variables and given/known data
    A Gamma photon is used in order to dissociate deuterium into a proton and neutron. the binding energy is 2.22Mev anf the rest energies for the proton and neutron are 938Mev and 939Mev respectively. determine the minmum photon energy to achieve this. consider two cases:
    1- both proton and neutron acquire collinear equal velocities parallel to the photon momentum
    2-the neutron stays staionary after the collission
    3- why non-collinear not considered in this analysis

    2. Relevant equations

    3. The attempt at a solution

    my answer for 1:

    Binding energy= (total number of proton and neutron)- minimum photon energy



    for part 2:

    since the neutron is stationary so this mean we have a zero energy for neutron and we will left only with proton energy and the minimum photon energy in this case would be:


    for part 3:

    for non-collinear this is because the momentum is not conserved
  2. jcsd
  3. May 18, 2008 #2
    no one have an idea for my Q if i am on the wr8 track o not
  4. May 19, 2008 #3
    59 viewers no one can help me
  5. May 20, 2008 #4


    User Avatar
    Homework Helper

    Hi matt222,

    I believe the binding energy is equal to the difference in rest mass between the combined proton+neutron and the separated proton and neutron. An energy of 2.22 MeV is required to separate the proton and neutron. If the energy added were exactly equal to the binding energy, then the proton and neutron would end up with zero kinetic energy.

    However, in this case, with a high energy photon causing the separation, more than just energy needs to be conserved. What does that mean the minimum photon energy needs to be?
  6. May 20, 2008 #5
    binding energy can also be the minimum energy required to decompose a molecule, an atom, or a nucleus into its components. So I agree with alphysicist.
  7. May 21, 2008 #6


    User Avatar
    Homework Helper


    For your answer to part 3: Could you explain your reasoning more fully? What leads you to that conclusion?
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?

Similar Discussions: Gamma photon momentum
  1. Momentum of a photon (Replies: 3)

  2. Photon momentum (Replies: 4)

  3. Momentum of photon (Replies: 3)

  4. Momentum of a photon (Replies: 9)