Two gas containers with volume of 100cm3 and 1000cm3 respectively are connected by a tube of negligible volume, and contain air at a pressure of 1000mm mercury. If the temperature of both vessels is originally at 273K. and the temperature of the smaller container is raised to 373K. How much air will pass through the connecting tube? (Give your answer in cm3 at 273K and 760mmHg) Well, i feel that this Q is weird. I know that the true solution is to find the decrease of mole in 100cm3. But i found sth weird. If i use P1V1/T1 = P2V2/T2, and use V2-V1, the answer is the same. (Approximately 33cm3) May i know whether the second solution works?