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Gas Equilibrium problem

  1. Mar 17, 2004 #1
    PCl5 <---> PCl3 + Cl2
    all are gases

    PCl5 is 45% decomposed
    if .110 mol of PCl5 is put in a 1.00 L container, what will
    be the equilibrium concentrations of PCl5, PCl3, and Cl2?

    PCl5 = .110 * .45 = .0495
    .110-.0495= .0605 mol/L

    so I've got .0605 mol/L for all 3 since all have the
    same coeff. Is this how to solve?
     
  2. jcsd
  3. Mar 17, 2004 #2
    0.110 - 0.0495 = 0.0605

    So there's 0.0605 mol of PCl5, but how much PCl5 reacted? Therefore how much product was formed?
     
  4. Mar 17, 2004 #3
    .0495 mol of PCl3
    .0495 mol of Cl2

    right?
     
  5. Mar 18, 2004 #4
    You got it.
     
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