Calculating Work Done by a Gas Expansion

In summary, the problem is to find the minimum amount of work that can be done by a gas as it expands from an initial state of (20 Pa, 3 m3) to a final state of (30 Pa, 17 m3). The gas is limited by a minimum pressure of 9 Pa and a maximum pressure of 40 Pa. The work done is equal to the change in pressure multiplied by the change in volume, or W = PΔV. The solution involves drawing a P-V diagram and finding a path from the initial to final state that minimizes the area under the path, which represents the work done. The maximum pressure plays no role in this problem, only the minimum pressure is relevant. The minimum
  • #1
IniquiTrance
190
0

Homework Statement



A gas is initially at (20 Pa, 3 m3) and expands to (30 Pa, 17 m3).

The minimum amount of pressure the gas can be under is 9 Pa, and the maximum pressure the gas can be under is 40 Pa.

Find the minimum amount of work that can be done by the gas in going from its initial state to its final state.

Homework Equations



W = P[tex]\Delta[/tex]V

The Attempt at a Solution



The statement doesn't state whether heat is added to the system, or whether the gas temperature changes. If the temperature varies, then P, V, and T all vary, so not sure how to approach this.

p.s., the answer provided is 126 J.

Thanks!
 
Physics news on Phys.org
  • #2
Well, a tricky one :smile:
They only ask for the work done by the gas, so focus on it. They leave you no clue about the process, so you can make up any process, as long as the work is minimum and the pressure doesn't go beyond its limits.
My suggestion: Draw the P-V diagram, and in that diagram, draw a path from point (20 Pa, 3m^3) to point (30 Pa, 17m^3) so that the area under the path is minimum, as the work = that area. You will see that the maximum pressure has no important role in this problem, only the minimum one does :smile:
 

What is the definition of work done by a gas expansion?

The work done by a gas expansion refers to the energy transferred by a gas as it expands against a constant external force. It is a measure of the change in the system's internal energy due to the expansion.

How is the work done by a gas expansion calculated?

The work done by a gas expansion can be calculated using the equation W = PΔV, where W represents work, P represents pressure, and ΔV represents the change in volume. This equation assumes that the external pressure is constant during the expansion.

What units are used to measure work done by a gas expansion?

The SI unit for work is joules (J). However, the work done by a gas expansion is often expressed in units of liters-atmospheres (L·atm) or kilojoules (kJ).

How does the work done by a gas expansion affect the temperature and pressure of the gas?

The work done by a gas expansion causes a decrease in the gas's temperature and pressure. This is due to the decrease in the gas's internal energy as it expands and does work against the external force.

What factors can affect the work done by a gas expansion?

The amount of work done by a gas expansion is affected by the initial and final volumes of the gas, the external pressure against which the gas expands, and the temperature of the gas. Additionally, the type of gas and the presence of any external heat sources can also affect the work done by a gas expansion.

Similar threads

  • Introductory Physics Homework Help
Replies
13
Views
762
  • Introductory Physics Homework Help
Replies
1
Views
476
  • Introductory Physics Homework Help
Replies
2
Views
839
  • Introductory Physics Homework Help
Replies
4
Views
923
  • Introductory Physics Homework Help
Replies
2
Views
513
  • Introductory Physics Homework Help
Replies
5
Views
627
  • Introductory Physics Homework Help
Replies
11
Views
3K
  • Introductory Physics Homework Help
Replies
4
Views
1K
  • Introductory Physics Homework Help
Replies
9
Views
2K
  • Introductory Physics Homework Help
Replies
8
Views
723
Back
Top