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Gas Law Help!

  1. Dec 6, 2012 #1
    1. The problem statement, all variables and given/known data

    bar of metal is at temperature T1 = 678 °C. Suppose the average kinetic energy of the molecules in the metal is multiplied by constant a = 9.49. Find T2, the new Celsius temperature.

    2. Relevant equations

    [itex]KE_{avg} = 3/2 kT[/itex]

    3. The attempt at a solution

    I worked out this way:

    [itex]KE_{avg} = 3/2 kT_{1}[/itex]
    [itex]aKE_{avg} = 3a/2 kT_{1}[/itex]
    [itex]3a/2 kT_{1} = 3/2 kT_{2}[/itex]
    [itex]aT_{1} = T_{2}[/itex]
    [itex]9.49 * (678 + 273) - 273 = T_{2}[/itex]
  2. jcsd
  3. Dec 6, 2012 #2
    Is it correct, or did I do something wrong?
  4. Dec 7, 2012 #3


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    Looks right to me.
  5. Dec 7, 2012 #4

    rude man

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