# Gas Law Help!

1. Dec 6, 2012

### NasuSama

1. The problem statement, all variables and given/known data

bar of metal is at temperature T1 = 678 °C. Suppose the average kinetic energy of the molecules in the metal is multiplied by constant a = 9.49. Find T2, the new Celsius temperature.

2. Relevant equations

$KE_{avg} = 3/2 kT$

3. The attempt at a solution

I worked out this way:

$KE_{avg} = 3/2 kT_{1}$
$aKE_{avg} = 3a/2 kT_{1}$
$3a/2 kT_{1} = 3/2 kT_{2}$
$aT_{1} = T_{2}$
$9.49 * (678 + 273) - 273 = T_{2}$

2. Dec 6, 2012

### NasuSama

Is it correct, or did I do something wrong?

3. Dec 7, 2012

### haruspex

Looks right to me.

4. Dec 7, 2012

right.