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Gas Law Help!

  • Thread starter NasuSama
  • Start date
326
3
1. Homework Statement

bar of metal is at temperature T1 = 678 °C. Suppose the average kinetic energy of the molecules in the metal is multiplied by constant a = 9.49. Find T2, the new Celsius temperature.

2. Homework Equations

[itex]KE_{avg} = 3/2 kT[/itex]

3. The Attempt at a Solution

I worked out this way:

[itex]KE_{avg} = 3/2 kT_{1}[/itex]
[itex]aKE_{avg} = 3a/2 kT_{1}[/itex]
[itex]3a/2 kT_{1} = 3/2 kT_{2}[/itex]
[itex]aT_{1} = T_{2}[/itex]
[itex]9.49 * (678 + 273) - 273 = T_{2}[/itex]
 
326
3
Is it correct, or did I do something wrong?
 

haruspex

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Looks right to me.
 

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