1. The problem statement, all variables and given/known data If 1.3 mol of a gas in a container occupies a volume of 9.0 L at a pressure of 1.2 atm, what is the temperature of the gas? 2. Relevant equations PV=nRT 3. The attempt at a solution The pressure is in atm so I converted it to Pascals and got 121560 Pa, then I plugged that into the gas law equation to solve for T PV/nR=T.... so ((121560)(9.0))/((1.3mol)(8.3)) and I got 101393.88 K, but that is wrong? Can you find my istake?