# Gas Law Problem

1. Nov 29, 2007

### sheri1987

1. The problem statement, all variables and given/known data
If 1.3 mol of a gas in a container occupies a volume of 9.0 L at a pressure of 1.2 atm, what is the temperature of the gas?

2. Relevant equations

PV=nRT

3. The attempt at a solution

The pressure is in atm so I converted it to Pascals and got 121560 Pa, then I plugged that into the gas law equation to solve for T

PV/nR=T.... so ((121560)(9.0))/((1.3mol)(8.3)) and I got 101393.88 K, but that is wrong? Can you find my istake?

2. Nov 29, 2007

### rock.freak667

Convert 9L to m$^3$

3. Nov 29, 2007

### stewartcs

Either change liters to cubic meters or change the gas constant's value to the proper units.

4. Nov 29, 2007

### stewartcs

Opps...too slow.

5. Nov 29, 2007

### sephirothrr

8.31 is in J/mol * K.
The gas constant you probably want is .08206 L * Atm / K * mol.
Using that constant, you won't need to change any units, and this becomes a simple number-crunching problem.

I hope that wasn't too much of a giveaway.