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Gas Law Problem

  1. Nov 29, 2007 #1
    1. The problem statement, all variables and given/known data
    If 1.3 mol of a gas in a container occupies a volume of 9.0 L at a pressure of 1.2 atm, what is the temperature of the gas?



    2. Relevant equations

    PV=nRT

    3. The attempt at a solution

    The pressure is in atm so I converted it to Pascals and got 121560 Pa, then I plugged that into the gas law equation to solve for T

    PV/nR=T.... so ((121560)(9.0))/((1.3mol)(8.3)) and I got 101393.88 K, but that is wrong? Can you find my istake?
     
  2. jcsd
  3. Nov 29, 2007 #2

    rock.freak667

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    Homework Helper

    Convert 9L to m[itex]^3[/itex]
     
  4. Nov 29, 2007 #3

    stewartcs

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    Science Advisor

    Either change liters to cubic meters or change the gas constant's value to the proper units.
     
  5. Nov 29, 2007 #4

    stewartcs

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    Opps...too slow.
     
  6. Nov 29, 2007 #5
    8.31 is in J/mol * K.
    The gas constant you probably want is .08206 L * Atm / K * mol.
    Using that constant, you won't need to change any units, and this becomes a simple number-crunching problem.

    I hope that wasn't too much of a giveaway.
     
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