Gas Law problem

1. Apr 16, 2005

apchemstudent

I don't seem to be able to get close to any of the choices given.

Here's my work: 288 K = T
P = 101.23 kPa

2% volume = water vapor

Well the next day the pressure changes to 100.47 kPa at the same temperature. The volume changes by 101.23/100.47 = 1.008....

I'm stuck here.... Can some one help? Thanks

Attached Files:

• Gas Law question.jpg
File size:
25.3 KB
Views:
50
Last edited: Apr 17, 2005
2. Apr 17, 2005

apchemstudent

any idea on how to solve this problem?

3. Apr 17, 2005

Hessam

pressure and volume are not directly proportional... perhaps this helps?

4. Apr 17, 2005

GCT

by avogadro's law the volume percent is equivalent to the mole percentage. In addition the mole percentage is equal to the pressure percentage (by dalton's law of partial pressures). Keep this in mind for the rest of this post.

I got one percent.
$$[100.47-(101.23-.02(101.23))]/100.47$$

I'm still not quite sure why they gave the molecular weight of gases in the problem, PV=nRT does not depend on mass composition. It's a colligative property

Once you find the final answer, please be considerate enough to tell the rest of us.