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Homework Help: Gas Law Problems

  1. Mar 9, 2004 #1
    Gas Law Problems
    A gas-filled balloon occupies a 4-L volume at a pressure of 300kPa. What volume will the balloon occupy if it rises to a height of where the pressure is 200kPa?

    Calculate the hieght to which a pressure of one atmosphere can life a column of water. Mercury is 13.6 times as dense as water.

    a 60-m^3 volume of gasy is at a temperature of 27 degrees Celsius. Under constant pressure the gas is cooles to -73 degrees Celsius. Calculate the new volume of gas.

    While held at a constant pressure, 12 L of gas are heated at 127.5 degrees celsius. If the new volume is 18L, what was the original temperature of the gas in degrees celsius?

    A gas is kept in a closed container at 620kPa. The gas is heated from 100 degrees celsius to 300 degrees celsius. Calculate the new pressure of the gas.

    a 6.0-L volume of gas has a pressure of 140 kPa and a temperature of -14 degrees celsius. What will be the pressure of this gas if the volume is reduced to 1.5 L and the temperature raised to 504 degrees celsius?

    The density of air is 1.3g/L at standard conditions of 101 kPa and 0 degrees celsius. Determine the mass of 3.0 L of ait at a pressure of 138.2 kPa and a temperature of 273 degrees celsius.

    One atmosphere of air pressure supports a column of water approximately 10.3 m high. A 2.0 cm^3 bubble of air is released by a diver working 62.4 m below the surface of a deep lake. If its temperature remains constant, what is the volume of the bubble as it reaches the surface? Hint: the pressure on the surface of the lake is on atm.
  2. jcsd
  3. Mar 9, 2004 #2
    I think these can all be solved using the ideal gas law, pv=nrt

    Since you didn't ask specificly for direction and have shown no work, this is about the most help you can expect to get here.


    and the answer is in another problem:
  4. Mar 9, 2004 #3
    I just got done with this lesson in chemistry. Most of those can be solved using the Boyle's Law and Combined Gas Law.

    boyle's law - P1/P2 = V2/V1

    Combined gas law - P1V1/T1 = P2V2/T2


    *You might have to get P1 by using PG=Patm-Hg or PG=Patm-Hg-H2O

    *Remember to change Celsius to Kelvins (C + 273)

    There's some problems on there I don't know how to do.

    I dont know why this is on a general physics forum. I've haven't had
    physics yet. Am I going to see Gas Law again?
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