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P1 = 9.00 atm

V1 = 2.00 L

P2 = ?

V2 = 6.0 L

Use P1V1 = P2V2, where P2 = (P1*V1)/(V2) = (9.00atm*2.00L)/(6.0 L) = 3.0 atm??

delta P (change in P) = P2 - P1 = 3.0 atm - 9.00 atm = -6.0 atm?? (correct significant digits?)

2) A combustion cylinder (containing a fixed number of moles of gas initially with a pressure of 4.00atm ) with a fixed piston changes temperature from 9.00 kelvin to 4.00 kelvin. Determine the change in pressure during this action.

P1 = 4.00 atm

T1 = 9.00 K

P2 = ?

T2 = 4.00 K

Use P1/T1 = P2/T2, where P2 = (P1*T2)/(T1) = (4.00 atm)(4.00 K)/(9. 00K) = 1.7778 atm??

Change in pressure (delta P) = P2 - P1 = 1.78 atm - 4.00 atm = -2.22 atm???

Thank you for any help.