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## Homework Statement

Into a 56[liter] container oxigen is filled in with manometric pressure of 4[atm] and temp' 47

^{0}C. what is the mass.

Then a leak happens and the pressure drops to 3.5[atm] and temp' 27

^{0}C.

How much oxigen escaped.

## Homework Equations

$$PV=nRT$$

$$R\left[\frac{liter\cdot atm'}{mole\cdot ^0K}\right]=0.08208$$

Atomic number O

_{2}=16

## The Attempt at a Solution

The initial conditions: ##3[atm]\cdot 56[liter]=n\cdot 0.08208\cdot 320^0K\rightarrow n=6.4[mole]##

$$m=6.4\cdot 16=102.3[gr]$$

Second stage:

$$\frac{P_1V_1}{n_1T_1}=\frac{P_2V_2}{n_2T_2}\rightarrow\frac{P_1V_1}{m_1T_1}=\frac{P_2V_2}{m_2T_2}$$

Our volume is fixed, so: ##\frac{3}{102.3\cdot 320}=\frac{2.5}{m_2\cdot 300}\rightarrow m_2=90.97[gr]##

Is it correct?