1. The problem statement, all variables and given/known data (The chemical equation is attached) Problem: Just before running, Sarah eats two oranges. Oranges provide her body with 25 grams of glucose which allows it to produce energy. The external temperature is 27 C, and atmospheric pressure is 102.3 kPa. While 21% of the air Sarah inhales is composed of O2, she exhales approximately 16% of the oxygen, In other words, she only uses 5% of the oxygen she inhaled. 1. How many litres of air does Tala inhale as she runs to burn the glucose consumed? 2. How many litres of water vapour does she produce? 3. How many litres of carbon dioxide does she produced? 2. The attempt at a solution Part 1 25 grams of glucose = (1250/9009) moles of glucose. Oxygen is 6 times the moles of glucose, thus, (7500/9009) moles of O2 Determining the litres of air: (102.3)(V)=(7500/9009)(8.314)(27+273.15) V = 20.31 Litres of O2 Part 2 & 3 25 grams of glucose = (1250/9009) moles of glucose. Oxygen is 6 times the moles of glucose, but only 5% of it is used, therefore: ((1250 * 6) / (9009)) * 0.05 = 125/3003 moles of O2 are used. This is now the limiting reactant. (102.3)(v)=(125/3003)(8.314)(27+273.15) V = 1.02 litres of CO2 and H2O each. Note: When they stated "oranges", I assumed that both of the oranges provided 25 grams of glucose in total.