The Question is in the paint document. My question to this problem is at the bottom of thread 1 Equation: T = T3/P3P. Where T3 is the temperature (K) of water at triple point I am not 100% sure what P and P3 stand for (can someone tell me) I believe P is the net pressure (Pressure supplied by the bulb minus the pressure opposing the pressure supplied by the bulb) and P3 is the pressure at triple point. Solution: All Temp are in Kelvin (K) Define: TL = Temp of left bulb PL = Pressure of left bulb TR = Temp of right bulb PR = Pressure of right bulb First Step: Let TL = T3 and TR = Boiling Point of Water = (BP) TL - TR = T3 - (BP) = T3/P3(PL - PR) Because (TL - TR)<0 Then (PL - PR) = -120torr. Solving for P3: P3 =T3(PL - PR)/(T3 - (BP)) Second Step: Let TL = T3 and TR = Unknown Temp. (T) TL - TR = T3 - T = T3/P3(PL - PR) Solving for T: T = T3 - T3/P3(PL - PR) QUESTION: Because I dont know If T>T3 or T<T3 I do not know whether (PL - PR) = +90torr or -90torr. How am I suppose to know?