Gauss hypergeometric function derivative

In summary, the Gauss hypergeometric function can be differentiated using the chain rule, with the derivative of the fourth parameter and the function itself being taken into account.
  • #1
fred_91
39
0

Homework Statement



I want to differentiate the Gauss hypergeometric function:
[itex]_2F_1[a,b;c;\frac{k-x}{z-x}][/itex]
with respect to z

Homework Equations



The derivative of
[itex]_2F_1[a,b;c;z][/itex]
with respect to z is:
[itex]\frac{ab}{c} _2F_1[1+a,1+b;1+c;z][/itex]

The Attempt at a Solution


Can I treat this as any other function, i.e., the same as with z in the fourth parameter but multiplied by the derivative of the fourth parameter:

[itex]\frac{ab}{c} _2F_1[a,b;c;\frac{k-x}{z-x}]\frac{-(k-x)}{(z-x)^2}[/itex]

If the fourth parameter was sin(z). Would the derivative of
[itex]_2F_1[a,b;c;\sin(z)][/itex]
with respect to z
be
[itex]\frac{ab}{c} _2F_1[1+a,1+b;1+c;sin(z)]cos(z)[/itex]?

Thank you in advance.
 
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  • #2


I would like to offer some guidance on how to approach differentiating the Gauss hypergeometric function.

Firstly, it is important to understand the properties and rules of differentiation. In this case, we can use the chain rule to differentiate the function with respect to z. This means that we need to consider the derivative of the fourth parameter (in this case, \frac{k-x}{z-x}) and the derivative of the function itself.

The derivative of the fourth parameter can be calculated using the quotient rule, which gives us:

\frac{d}{dz}(\frac{k-x}{z-x}) = \frac{(z-x)\frac{d}{dz}(k-x) - (k-x)\frac{d}{dz}(z-x)}{(z-x)^2} = \frac{k-x}{(z-x)^2}

Now, using the chain rule, we can write the derivative of the function as:

\frac{d}{dz}(_2F_1[a,b;c;\frac{k-x}{z-x}]) = \frac{d}{dz}(_2F_1[a,b;c;u]) \frac{d}{dz}(\frac{k-x}{z-x}) = \frac{ab}{c} _2F_1[1+a,1+b;1+c;\frac{k-x}{z-x}] \frac{k-x}{(z-x)^2}

Therefore, the final answer would be:

\frac{ab}{c} _2F_1[1+a,1+b;1+c;\frac{k-x}{z-x}] \frac{k-x}{(z-x)^2}

To answer your second question, the derivative of the function with respect to z when the fourth parameter is sin(z) would be:

\frac{ab}{c} _2F_1[1+a,1+b;1+c;\sin(z)]\cos(z)

I hope this helps you in your understanding of differentiating the Gauss hypergeometric function. Remember to always carefully consider the properties and rules of differentiation when approaching a new function.
 

1. What is the Gauss hypergeometric function derivative?

The Gauss hypergeometric function derivative, also known as the Gaussian hypergeometric derivative, is a mathematical function that is a derivative of the Gauss hypergeometric function. It is often denoted as F' or F1.

2. What is the formula for the Gauss hypergeometric function derivative?

The formula for the Gauss hypergeometric function derivative can be written in terms of the hypergeometric series as F'1(a,b;c;z) = (a+1)F(a+1,b;c+1;z). It can also be expressed in terms of the confluent hypergeometric function as F'1(a,b;c;z) = (c-z)F1(a+1,b+1;c+1;z).

3. What are the applications of the Gauss hypergeometric function derivative?

The Gauss hypergeometric function derivative has many applications in mathematics and physics. It is used to solve various differential equations, including the hypergeometric differential equation. It also has applications in probability theory, combinatorics, and special functions.

4. What are the properties of the Gauss hypergeometric function derivative?

The Gauss hypergeometric function derivative shares many properties with the original hypergeometric function, such as the transformation formulas and recurrence relations. It is also a meromorphic function with poles at negative integers. Additionally, it has a singularity at z=1, where it is not defined.

5. How is the Gauss hypergeometric function derivative related to other special functions?

The Gauss hypergeometric function derivative is closely related to other special functions, such as the hypergeometric function, confluent hypergeometric function, and the Meijer G-function. It can also be expressed in terms of the Appell hypergeometric function. Furthermore, it has connections to other mathematical concepts, such as hyperbolic geometry and elliptic curves.

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