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I used the equation [tex] \Phi = E*4\pi r^2 [/tex] and then the equation [tex] \Phi = q_e_n_c /E_0 [/tex] and set them equal to each other. I used the formula q_e_n_c = charge/volume * volume to get [tex] Q/(4/3)\pi R^3 * (4/3)\pi r^3. [/tex] Simplifying gave me [tex] Qr^3/E_0 R^3 [/tex]. Plugging this in for q_e_n_c and solving for the E field gave me ,

[tex] E= Qr/ E_0R^3*4\pi [/tex]

Q= 2 x 10^-12 since the charge is uniform

r =.018 m

E_0 = 8.85 x 10^-12

R= .033

So 2 x 10^-12(.018)/8.85 x 10^-12 *(.033)^3 * 4pi = 9.02 N/C.... which isn't right.

Can someone please help me? I have no idea what I'm doing.