- #1
HelpMeh
- 13
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So I was doing some practice problems and one of them asked for the flux through one side of a cube that has a point charge(Q) at its center, it seems intuitive that it would be 1/6 of the charge but how would i show this?
if I do
∫E dA → E∫dA
the surface area of a cube is 6L2 so i would get
E*6L2=Q/ε0
then?
thanks.
if I do
∫E dA → E∫dA
the surface area of a cube is 6L2 so i would get
E*6L2=Q/ε0
then?
thanks.