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Gauss' Law for a plane

  1. Jun 7, 2012 #1
    The electric field 0.475m from a very long uniform line of charge is 830 N/C.

    How much charge is contained in a section of the line of length 3.00cm?

    My solution:
    the Electric field from an infinite plane is

    E=σ/(2*ε0), so σ=E*ε0*2=1.47*10^-8

    3.00cm=.03m

    .03*1.47*10^-8=4.41*10^-10

    This answer is showing to be wrong
     
  2. jcsd
  3. Jun 7, 2012 #2
    Just realized my problem was that my work was for a plane, not a line of charge. I'm not sure how to solve this for a line of charge though
     
  4. Jun 7, 2012 #3

    vela

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    A line charge has a cylindrical symmetry, so apply Gauss's Law using a cylinder as your Gaussian surface.
     
  5. Jun 12, 2012 #4
    Thanks for the help, forgot to reply at the time due to my astonishment that I had not thought of that.
     
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