Gauss law for continuous charge distribution

  1. gaussian surface can be taken passing through continuous charge can a surface of hollow sphere be assumed as a gaussian surface to find field at that point? if you assume so you will get charge enclosed to be zero which says field is zero.but this is not the actual case which says field is kq/R^2

    note: gaussian surface is not just above sphere surface...but the surface itself
    Last edited by a moderator: Jan 21, 2014
  2. jcsd
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