Gauss' Law in Dielectrics Part II

1. Nov 17, 2004

joshanders_84

OK I just want to start from the beginning and try to get the first part of this problem so I can get what is going on in my head and understand it. Here's the problem:

A point charge q is imbedded in a solid material of dielectric constant K.

A) Use Gauss's law as stated in equation $$\oint{K \vec{E} \cdot \vec{A}} \;=\; \frac{Q_{free}}{\epsilon_{0}}$$ to find the magnitude of the electric field due to the point charge q at a distance d from the charge.

So how does it effect what is going on? I mean the dielectric? I don't get it!

2. Nov 17, 2004

wisper

E = q/(4*pi*K*(epsilon_0)*(d^2))