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[tex]\nabla \cdot \vec{E} = \frac{\rho}{\epsilon_0}[/tex].

So the divergence of the electric field is the chargedensity divided by epsilon zero.

I just wondered.. since divergence is a local or "point" property. Is the chargedensity in this law also the charge density at that point? That is to say for some x,y,z is

[tex]\nabla \cdot \vec{E}(x,y,z) = \frac{\rho (x,y,z) }{\epsilon_0}[/tex]?